The number of minutes spent by two students, XX and YY, exercising every day in a given week are shown in the bar chart above. The number of days in the given week in which one of the students spent a minimum of 10%10% more than the other student, on a given day, is

GATE 2021 PREVIOUS QUESTION PAPER

GENERAL APTITUDE

ELECTRONICE & COMMUNICATION 2021 GATE EXAM 

The number of minutes spent by two students, X$X$ and Y$Y$, exercising every day in a given week are shown in the bar chart above.

The number of days in the given week in which one of the students spent a minimum of 10%$10\mathrm{\%}$ more than the other student, on a given day, is

(A) 4 

(B) 7 

(C) 6 

(D) 5

ANSWER : C

We can calculate the number of days in the given week in which one of the students spent more time than the other.

If X$X$ is more than 10%$10\mathrm{\%}$ of Y$Y$ then Y$Y$ should be minimum and vice-versa.

• On Monday, the required percentage =(70−4545)×100%=55.55%$=\left({\displaystyle \frac{70-45}{45}}\right)\times 100\mathrm{\%}=55.55\mathrm{\%}$
• On Tuesday, the required percentage =(65−5555)×100%=18.18%$=\left({\displaystyle \frac{65-55}{55}}\right)\times 100\mathrm{\%}=18.18\mathrm{\%}$
• On Wednesday, the required percentage =(60−5050)×100%=20%$=\left({\displaystyle \frac{60-50}{50}}\right)\times 100\mathrm{\%}=20\mathrm{\%}$
• On Thursday, the required percentage =(60−5555)×100%=9.09$=\left({\displaystyle \frac{60-55}{55}}\right)\times 100\mathrm{\%}=9.09$
• On Friday, the required percentage =(35−2020)×100%=75%$=\left({\displaystyle \frac{35-20}{20}}\right)\times 100\mathrm{\%}=75\mathrm{\%}$
• On Saturday, the required percentage =(60−5050)×100%=20%$=\left({\displaystyle \frac{60-50}{50}}\right)\times 100\mathrm{\%}=20\mathrm{\%}$
• On Sunday, the required percentage =(65−5555)×100%=18.18%$=\left({\displaystyle \frac{65-55}{55}}\right)\times 100\mathrm{\%}=18.18\mathrm{\%}$

∴$\therefore$ Total 6$6$ days are there, when one of the students spent a minimum of 10%$10\mathrm{\%}$ more than the other student.