a) -2.8psnm -1 km -1
b) -3.76psnm -1 km -1
c) -1.2psnm -1 km -1
d) 2.4psnm -1 km -1
Answer : - 3.76psnm -1 km -1
The total first order dispersion for fiber at two wavelength is obtained by
D T (1260 nm) = λS 0 /4 [1-(λ 0 /λ) 4 ]
= (1260*0.08*10 -12 )/4 * (1-[1550/1260] 4 )
= -3.76psnm -1 km -1
Where
λ 0 = zero dispersion wavelength
λ = wavelength
S 0 = dispersion slope
D T = total first order dispersion.
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